|
|
文章數：113 |
 ~~~~~~~~~~~~~~~€高二數學~~~~~~~~~~~~~~~~~~~~~~~~ |
| 在地生活｜中彰投 2017/08/03 00:27:50 |
標題:
此文章來自奇摩知識+如有不便請留言告知 ~~~~~~~~~~~~~~~€高二數學~~~~~~~~~~~~~~~~~~~~~~~~發問: 己知複數z滿足lzl<=1/2，求複數z-1的輻角主值的最大值和最小值。 吾該詳細解釋 最佳解答: 圖片參考：http://inlinethumb24.webshots.com/5271/2990746910100590278S600x600Q85.jpg In the Argand Diagram, |z|≤1/2 is represented by the whole area of a circle of centre (0,0) and radius 1/2. Accordingly, z-1 is represented by the whole area of a circle of centre (-1, 0) and radius 1/2. sin θ = (1/2) / 1 = 1/2 θ = π/6 So, the maximum of principle angle = π + π/6 = 7π/6 the minimum of principle angle = π - π/6 = 5π/6 其他解答: |
| 最新創作 |
|
||||
|
||||
|
||||
|
||||
|
||||
